Question

Помогите сделать……….........

Answer 1

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Answer 2

1)(2*(а²-9)-а*(а+3)-а*(а-3))/(а-3)²(а+3)=(2а²-18-а²-3а-а²+3а)/(а-3)²(а+3)=
-18/(а-3)²(а+3)
2)(4(х-у)+а(х-у))/(х²-у²)=(х-у)(4+а)/(х-у)(х+у)=(4+а)/(х+у)=(4+2)/(7,3-7,8)=6/(-0,5)=-12