Question

помогите пожалуйстаааа...​

Answer 1

$a {x}^{2} + bx + c = a(x -x_{1} )(x - x_{2})$

$2 {x}^{2} + 7x + 6 = 0 \\ a =2 \\ b = 7\\ c =6 \\ D = {b}^{2} - 4ac = {7}^{2} - 4 \times 2 \times 6 = \\ 49 - 48 = 1 \\ x _{1} = \frac{ - 7 + 1}{2 \times 2} = - \frac{6}{4} = - \frac{3}{2} = - 1.5 \\ x_{2} = \frac{ - 7 - 1}{ 2\times 2} = - \frac{8}{4} = - 2 \\ \\ 2 {x}^{2} + 7x + 6 = \\ 2(x - ( - 1.5))(x - ( - 2)) = \\ 2(x + 1.5)(x + 2) = (2x + 3)(x + 2)$

Ответы:

1

-1,5

-2

(2х+3)(х+2)