Question

x^2+3x-4/x+4 срочно пж

Answer 1

(x^2 + 3x - 4) : (x + 4)
(x + 4)(x - 1)
((x + 4)(x - 1)) : (x + 4)
x - 1

Answer 2

$\displaystyle\bf\\\frac{x^{2} +3x-4}{x+4} =\frac{(x^{2} -1)+(3x-3)}{x+4} =\\\\\\=\frac{(x-1)(x+1)+3(x-1)}{x+4} =\frac{(x-1)(x+1+3)}{x+4} =\\\\\\=\frac{(x-1)(x+4)}{x+4} =x-1$