Question

Тридцять третій прогресії:-10;-8;-6;…

Answer 1

$\displaystyle\bf\\a_{1} =-10\\\\a_{2} =-8\\\\a_{33} =?\\\\\\a_{2} =a_{1} +d\\\\d=a_{2} - a_{1} =-8-(-10)=-8+10=2\\\\a_{33}=a_{1} +32d=-10+32\cdot 2=-10+64=54\\\\Otvet \ : \ a_{33} =54$