Question

a) 12a5B3 18aB -; 6) 16x(x-y) 24y(x-y) В x2+x X2​

Answer 1

Ответ:

$\frac{12 {a}^{5} {b}^{3} }{18ab} = \frac{2 {a}^{4} {b}^{2} }{3}$

$\frac{16x(x - y)}{24y(x - y)} = \frac{2x}{3y}$

$\frac{ {x}^{2} + x }{x} = \frac{x(x + 1)}{x} = x + 1$