Question

2) sin 88⁰/ sin 22° cos 22° cos 44°​

Answer 1

$\displaystyle\bf\\\frac{Sin88^\circ}{Sin22^\circ Cos22^\circ Cos44^\circ} =\frac{2Sin44^\circ Cos44^\circ}{Sin22^\circ Cos22^\circ Cos44^\circ} =\\\\\\=\frac{2Sin44^\circ}{Sin22^\circ Cos22^\circ } =\frac{2\cdot 2Sin22^\circ Cos22^\circ}{Sin22^\circ Cos22^\circ } =4$