Question

2) 4(3x - 2) - 2(3x - 6) = 4x - 30 ,
-2 - 3(4 - 2x) + 6(2x - 1) = 4(5× - 2) ,
3 + 4x - 2(3 - x) - 7 = 2(x - 3) + 8 ,
-8x + 1(3x - 2) - * = -6(2 - x) + 7 ,
-4x - 5 + 6(2 - 3x) + 18x = 7x - 5 + x .
1: -1: -17; 3; -6


3) (-6× -3)(2x + 5) = 0
(-x - 5) (x - 2) = 0
3x - 1,8||4 - 5x = 0
0,6 і 0,8; -5 і 2; - 2,5 і -0,5


ПОЖАЛУЙСТА СРОЧНОО

Answer 1

a) 4(3x - 2) - 2(3x - 6) = 4x - 30

12x - 8 - 6x + 12 = 4x - 30

6x + 4 = 4x - 30

2x = -34

x = -17

b) -2 - 3(4 - 2x) + 6(2x - 1) = 4(5x - 2)

-2 - 12 + 6x + 12x - 6 = 20x - 8

18x - 8 = 20x - 8

2x = 0

x = 0

c) 3 + 4x - 2(3 - x) - 7 = 2(x - 3) + 8

3 + 4x - 6 + 2x - 7 = 2x - 6 + 8

6x - 10 = 2x + 2

4x = 12

x = 3

d) -8x + 13(3x - 2) - 5 = -6(2 - x) + 7

-8x + 39x - 26 - 5 = -12 + 6x + 7

31x - 31 = 6x - 5

25x = 26

x = 26/25

e) -4x - 5 + 6(2 - 3x) + 18x = 7x - 5 + x

-4x - 5 + 12 - 18x + 18x = 8x - 5

8x - 5 = 8x - 5

The solution is not unique, any value of x is a solution.

(-6x - 3)(2x + 5) = 0

Using the zero product property, we can set each factor to 0 and solve for x:

-6x - 3 = 0 or 2x + 5 = 0

-6x = 3 or 2x = -5

x = -1/2 or x = -5/2

Also, we have another equation:

(-x - 5)(x - 2) = 0

Using the zero product property:

-x - 5 = 0 or x - 2 = 0

x = -5 or x = 2

So the solutions for the equation are:

x = -1/2, -5/2, -5 or 2.