Question

Розв'яжіть систему рівнянь
2x-3(y+1)=-2
3(x+1)+3y=2y-1

Answer 1

$\displaystyle\bf\\\left \{ {{2x-3(y+1)=-2} \atop {3(x+1)+3y=2y-1}} \right. \\\\\\\left \{ {{2x-3y-3=-2} \atop {3x+3+3y=2y-1}} \right. \\\\\\\left \{ {{2x-3y=-2+3} \atop {3x+3y-2y=-1-3}} \right. \\\\\\\left \{ {{2x-3y=1} \atop {3x+y=-4} \ |\cdot 3} \right. \\\\\\+\left \{ {{2x-3y=1} \atop {9x+3y=-12}} \right. \\----------\\11x=-11\\\\x=-11:11=-1\\\\y=-4-3x=-4-3\cdot(-1)=-4+3=-1\\\\\\Otvet \ : \ (-1 \ ; \ -1)$