Question

найдите произведения корней уравнений
|3-|2+x||=1
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Answer 1

$\displaystyle\bf\\\Big|3-|2+x|\Big|=1\\\\\\\left[\begin{array}{ccc}3-|2+x|=-1\\3-|2+x|=1\end{array}\right\\\\\\\left[\begin{array}{ccc}3+1=|2+x|\\3-1=|2+x|\end{array}\right\\\\\\\left[\begin{array}{ccc}|2+x|=4\\|2+x|=2\end{array}\right\\\\\\1) \ |2+x|=4\\\\\\\left[\begin{array}{ccc}2+x=-4\\2+x=4\end{array}\right\\\\\\\left[\begin{array}{ccc}x=-4-2\\x=4-2\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =-6\\x_{2} =2\end{array}\right\\\\\\2) \ |2+x|=2$

$\displaystyle\bf\\\left[\begin{array}{ccc}2+x=-2\\2+x=2\end{array}\right\\\\\\\left[\begin{array}{ccc}x=-2-2\\x=2-2\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{3} =-4\\x_{4} =0\end{array}\right\\\\\\x_{1} \cdot x_{2} \cdot x_{3}\cdot x_{4} =-6\cdot 2\cdot(-4)\cdot 0=0\\\\\\Otvet \ : \ 0$