Question

допоможіть:).........​

Answer 1

1) $y' = (x^{\frac{1}{9} })' = \frac{1}{9}*x^{\frac{-8}{9} }$

2) $y' = (x^{\frac{5}{6}})' = \frac{5}{6} * x^{\frac{-1}{6} }$

3) $y' = (x^{-\frac{7}{12} })' = -\frac{7}{12} * x^{-\frac{19}{12} }$

Answer 2

Ответ:

2) у=⁶√х^5

⁶√у^5=x

y^5=x^6

y=x ⁵√x

3)y=1/ ¹²√x^7

1=x ¹²√y^7

x ¹²√y^7=1

¹²√y^7=1/2

¹²√y^7=1/x

y^7=1/x^12

y=⁷√x^2/x^2

Объяснение:

1)y=⁹√x

x=⁹√y=x

y=x^9