Question

Розв'яжіть систему рівнянь, способом підстановки:
2x-3y=-6,
3x+1,5y=3.

Answer 1

$\displaystyle\bf\\\left \{ {{2x-3y=-6} \atop {3x+1,5y=3} |:3} \right. \\\\\\\left \{ {{2x-3y=-6} \atop {x+0,5y=1} } \right. \\\\\\\left \{ {{2\cdot(1-0,5y)-3y=-6} \atop {x=1-0,5y} } \right. \\\\\\\left \{ {{2-y-3y=-6} \atop {x=1-0,5y} } \right. \\\\\\\left \{ {{-4y=-8} \atop {x=1-0,5y} } \right. \\\\\\\left \{ {{y=2} \atop {x=1-0,5\cdot 2} } \right. \\\\\\\left \{ {{y=2} \atop {x=1-1} } \right. \\\\\\\left \{ {{y=2} \atop {x=0} } \right. \\\\\\Otvet \ : \ (0 \ ; \ 2)$