Question

решите уравнение 3(x-2)(x+4)=2x^2+x

Answer 1

$3(x - 2)(x + 4) = 2 {x}^{2} + x \\ (3x - 6)(x + 4) - 2{x}^{2} - x = 0 \\ 3 {x}^{2} + 12x - 6x - 24 - 2 {x}^{2} - x = 0 \\ {x}^{2} + 5x - 24 = 0 \\ {x}^{2} + 8x - 3x - 24 = 0 \\ x(x + 8) - 3(x + 8) = 0 \\ (x - 3)(x + 8) = 0 \\ x1 = 3 \\ x2 = - 8$