Предмет: Химия, автор: fvcyfv

Який об’єм водню (н. у.) виділиться у процесі взаємодії літій масою 180 г з хлоридною кислотою?

Ответы

Автор ответа: fhfdvb1258

Ответ:Уравнение химической реакции 2Li + 2HCl → 2LiCl + H2.

n(Li) = m(Li) : M(Li) = 180 г : 7 г/моль ≈ 25,7 моль.

По уравнению химической реакции n(H2) = n(Li) : 2 = 25,7 моль : 2 = 12,85 моль.

V(H2) = n(H2)*Vm = 12,85 моль*22,4 л/моль = 287,84 л при нормальных условиях.

Объяснение:Відповідь:287,84 л

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