Question

Помогите бистрейййй пожалуйста

Answer 1

1)

$( \frac{ {81}^{3} }{ {343}^{2} } ) {}^{ \frac{1}{6} } = \frac{ {81}^{ \frac{3}{6} } }{343 {}^{ \frac{2}{6} } } = \frac{ {81}^{ \frac{1}{2} } }{ {343}^{ \frac{1}{3} } } = \\ \frac{ \sqrt{81} }{ \sqrt[3]{343 {}^{2} } } = \frac{ \sqrt{ {9}^{2} } }{ \sqrt[3]{(7 {}^{2} ) {}^{3} } } = \frac{9}{ {7}^{2} } = \frac{9}{49}$

2)

$\frac{ {81}^{ \frac{1}{3} } \times \sqrt[5]{4} }{3 {}^{ \frac{1}{3} } \times 2 {}^{ - 3.6} } = \frac{ {3}^{ \frac{4}{3} } \times 2 {}^{ \frac{2}{5} } }{3 {}^{ \frac{1}{3} } \times 2 {}^{ - \frac{18}{5} } } = 3 {}^{ \frac{4}{3} - \frac{1}{3} } \times {2}^{ \frac{2}{5} + \frac{18}{5} } = \\ 3 \times 2 {}^{4} = 3 \times 16 = 48$

3)

$\sqrt[4]{ \frac{3}{4} } \times \sqrt[4]{6 \frac{3}{4} } = \sqrt[4]{ \frac{3 \times 27}{4 \times 4} } = \sqrt[4]{ \frac{ {3}^{4} }{ {2}^{4} } } = \frac{3}{2} = 1.5$