Question

195. 1) 2) 5a(b- c) 15a(b-c)' 10a³b²(a+b). 14a²b(a + b) 3) 4) 46² (p+q) 116a²b¹ (p+q) ³ 22m³n5 (a - b) 11m5 n³ (a - b)*​

Answer 1

1) 1/3

$\frac{5a(b - c)}{15a(b - c)} = \frac{5a}{15a} = \frac{5}{15} = \frac{1}{3}$

2) 5а/7

$\frac{10 {a}^{3} {b}^{2} (a + b)}{14 {a}^{2}b(a + b)} = \frac{10 {a}^{3} {b}^{2} }{14 {a}^{2}b } = \frac{10 {a}^{3}b }{14 {a}^{2} } = \frac{10a}{14} = \frac{5a}{7}$

3) 1/29a²b²

$\frac{4 {b}^{2}(p + q) }{116 {a}^{2} {b}^{4} (p + q)} = \frac{4 {b}^{2} }{116 {a}^{2} {b}^{4} } = \frac{4}{116 {a}^{2} {b}^{2} } = \frac{1}{29 {a}^{2} {b}^{2} }$

4) 2n²/m²

$\frac{22 {m}^{3} {n}^{5}(a - b) }{11 {m}^{5} {n}^{3} (a - b)} = \frac{22 {m}^{3} {n}^{5} }{11 {m}^{5} {n}^{3} } = \frac{22 {m}^{3} {n}^{2} }{11 {m}^{5} } = \frac{22 {n}^{2} }{11 {m}^{2} } = \frac{2 {n}^{2} }{ {m}^{2} }$