Question

7. Разложите на множители :
а) 64а^4-49а^2b^2
б) (х-3)^2-25​

Answer 1

$\displaystyle\bf\\1)\\\\64a^{4} -49a^{2} b^{2} =a^{2} \cdot(64a^{2} -49b^{2} )=a^{2} \cdot\Big[(8a)^{2} -(7b)^{2}\Big]=\\\\\\=a^{2} \cdot(8a-7b)\cdot(8a+7b)\\\\2)\\\\(x-3)^{2} -25=(x-3)^{2} -5^{2} =(x-3-5)\cdot(x-3+5)=\\\\\\=(x-8)\cdot(x+2)$