Question

Помогите.Дам 25 балла.​

Answer 1

Ответ:

${x}^{2} + 2x - 15 = 0 \\ x1 + x2 = - 2 \\ x1 \times x2 = - 15 \\ \\ x1 = - 5 \: \: \: \: \: x2 = 3$

$4 {y}^{2} - 15y + 9 = 0 \\ d = 225 - 144 = 81 \\ \\ y1 = \frac{15 - 9}{8} = 0.75 \\ y2 = \frac{15 + 9}{8} = 3$

$\frac{ {x}^{2} - 2x - 8 }{ {x}^{2} - 16 } = \frac{(x - 4)(x + 2)}{(x - 4)(x + 4)} = \frac{x + 2}{x + 4}$

x ≠ ±4