Question

Пожалуйста решите ПО ТЕОРЕМЕ ВИЕТА
40 балов ​

Answer 1

Ответ:

Пошаговое объяснениетеорема вьета

x1+x2=-b/a

x1*x2=c/a

1) -x2+75x+574=0

x1+x2=75

x1*x2=-574

x1=82   x2= -7

2)x^2-16x+55=0

x1+x2=16

x1*x2=55

x1= 5 x2= 11

3)x^2+37x+330=0

x1+x2=-37

x1*x2=330

x1=-22  x2= -15

4)x^2-4x+3=0

x1+x2=4

x1*x2=3

x1=1 x2=3

5)-x^2-6x-9=0

x1+x2=-6

x1*x2=9  x1=x2=-3

6)x^2+3x+13=0

x1+x2=-3

x1*x2=13 решения нет(кореней)

7)x^2-30x+225=0

x1+x2=30

x1*x2=225 x1=x2=15

8)x^2-x-30=0

x1+x2=1

x1*x2=-30

x1=-5 x2=6

пожалуйста лучший ответ 5 звезд + лайк

Answer 2

$- {x}^{2} + 75x + 574 = 0 \\ {x}^{2} -7 5x - 574 = 0 \\ x _{1} + x _{2} = 75 \\ x _{1} \times x _{2} = - 574 \\ x _{1} = - 7\\ x _{2} = 82$

${x}^{2} - 16x + 55 = 0 \\ x _{1} + x _{2} =16 \\ x _{1} \times x _{2} = 55\\ x _{1} = 5\\ x _{2} = 11$

${x}^{2} + 37x + 330 = 0 \\ x _{1} + x _{2} = - 37 \\ x _{1} \times x _{2} = 330 \\ x _{1} = - 22\\ x _{2} = - 15$

${x}^{2} - 4x + 3 = 0 \\ x _{1} + x _{2} = 4 \\ x _{1} \times x _{2} = 3 \\ x _{1} = 1\\ x _{2} = 3$

$- {x}^{2} - 6x - 9 = 0 \\ {x}^{2} + 6x + 9 = 0 \\ (x + 3) {}^{2} = 0 \\ x + 3 = 0 \\ x = - 3$

${x}^{2} + 3x + 13 = 0 \\ d = 3 {}^{2} - 4 \times 13 = 9 - 52 = - 43 \\ d < 0$

нет решений

${x}^{2} - 30x + 225 = 0 \\ (x - 15) {}^{2} = 0 \\ x - 15 = 0 \\ x = 15$

${x}^{2} - x - 30 = 0 \\ x _{1} + x _{2} =1 \\ x _{1} \times x _{2} = - 30 \\ x _{1} = 6 \\ x _{2} = - 5$