Question

Буду дуже вдячний за допомогу <3

Answer 1

<DCH = 90° - <CDH = 90° - 60° = 30°

-> HD = 1/2 CD = 1/2 × 6 = 3 см

АD = AK + KH + HD = 1 + 4 + 3 = 8 см

CD² = HD² + CH²

CH² = CD² - HD²

$ch = \sqrt{ {cd}^{2} - {hd}^{2} } = \sqrt{ {6}^{2} - 3 {}^{2} } = \\ \sqrt{(6 - 3)(6 + 3)} = \sqrt{3 \times 9} = 3 \sqrt{3} \: \: cm$