Question

. Обчисліть:
a) 1/3--5-/1,44;
16
в) /72:/2;
6) √3-√√7,5;
r) (-3/2)²

Answer 1

$\sqrt{3 \frac{1}{16} } - 5 \sqrt{1.44} = \sqrt{ \frac{49}{16} } - 5 \sqrt{1.2 {}^{2} } = \\ \sqrt{ \frac{ {7}^{2} }{ {4}^{2} } } - 5 \times 1.2 = \frac{7}{4} - 6 = \\ 1.75 - 6 = - 4.25$

$\sqrt{3 \frac{1}{3} } \times \sqrt{7.5} = \sqrt{ \frac{10}{3} \times7 .5 } = \\ \sqrt{ \frac{10 \times 75}{3 \times 10} } = \sqrt{25} = \sqrt{ {5}^{2} } = 5$

$\sqrt{72} \div \sqrt{2} = \sqrt{72 \div 2} = \sqrt{36} = \\ \sqrt{ {6}^{2} } = 6$

$( - 3 \sqrt{2} ) {}^{2} = 9 \times 2 = 18$