Question

Помогите срочно !!!!!!!!!20б

Answer 1

$\displaystyle\bf\\2x^{2} -32=0 \ |:2\\\\x^{2} -16=0\\\\x^{2} =16\\\\x_{1,2} =\pm \ \sqrt{16} =\pm \ 4\\\\Otvet \ : \ x_{1}=4 \ \ , \ \ x_{2} =-4$