Question

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2×2^3
2^2×2n
8×2k
4^2×2m
2n×2m
4^2×8k
16m:8k

Answer 1

2 × 2^3 = 2^1 × 2^3 = 2^(1+3) = 2^4

2^2 × 2^n = 2^(2+n)

8 × 2^k = 2^3 × 2^k = 2^(3+k)

4^2 × 2^m = (2^2)^2 × 2^m = 2^(2*2+m) = 2^(4+m)

2^n × 2^m = 2^(n+m)

4^2 × 8^k = (2^2)^2 × (2^3)^k = 2^(22+3k) = 2^(4+3k)

16m:8k = (2^4)^m : (2^3)^k = 2^(4m-3k)