Question

Допоможіть вирішити хоча б один приклад що я зрозумів як робити другий

Answer 1

(3х-2)(3х+2) = 9x^2 - 4
(4х-5)^2 = 16x^2 - 40x + 25

So, the left side of the equation becomes:

9x^2 - 4 + 16x^2 - 40x + 25 = 25x^2 - 40x + 21

Now, we can rewrite the equation as:

25x^2 - 40x + 21 = 10x + 21

Subtracting 10x and 21 from both sides, we get:

25x^2 - 50x = 0

Factoring out 25x, we get:

25x(x - 2) = 0

Therefore, the solutions are:

x = 0 or x = 2/5.