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Answer 1

$10,35+(1\frac{2}{3} +\frac{37}{60} )*(67\frac{9}{16} -40-21\frac{9}{16} )-4,875:1,5=20,8\\1\frac{2}{3} +\frac{37}{60}=1\frac{40}{60} +\frac{37}{60}=1\frac{77}{60} =2\frac{17}{60}\\67\frac{9}{16} -40-21\frac{9}{16}=46-40=6\\2\frac{17}{60}*6=\frac{137*6}{60} =\frac{137}{10} =13,7\\4,875:1.5=3,25\\10,35+13,7-3,25=7,1+13,7=20,8$

$31\frac{21}{32} + ( 16\frac{3}{11} -15\frac{9}{11} +1\frac{8}{11} :0,6)*\frac{33}{64} *0,2-10\frac{1}{6} =21\frac{5}{6}\\1\frac{8}{11} :0,6=\frac{19*5}{11*3} =\frac{95}{33} \\16\frac{3}{11} -15\frac{9}{11}=15\frac{14}{11} -15\frac{9}{11}=\frac{5}{11} \\\frac{5}{11} +\frac{95}{33} =\frac{15+95}{33}=\frac{110}{33} \\\frac{110}{33} *\frac{33}{64} *0,2=\frac{110*33*1}{33*64*5} =\frac{11}{32} \\31\frac{21}{32} +\frac{11}{32}=31\frac{32}{32} =32\\32-10\frac{1}{6}=31\frac{6}{6} -10\frac{1}{6}=21\frac{5}{6}$