Question

P(v) + Cl (1) =
Cr(III) + O2 =
N2(III) + H2=
Li+ S(II) =
H2 + O2 =
Al + O2 =
Na + O2 =
H2 + S(II) =
К+ Н2=
Ba + O2 =
Fe(III) + 02=
Mn(VII) + O2 = ​

Answer 1

2P+5Cl2=>2PCl5

2Cr+3O2=>2CrO3

N2+3H2=>2NH3

2Li+S=>Li2S

2H2+O2=>2H2O

4Al+3O2=>2Al2O3

4Na+O2=>2Na2O

H2+S=>H2S

2K+H2=>2KH

2Ba+O2=>2BaO

4Fe+3O2=>2Fe2O3;

4Mn+7O2=>2Mn2O7