Предмет: Математика, автор: hitli899

(2y-3)2+(y-3)(y+3)+12y при у=-2 равно 20

Ответы

Автор ответа: iramazurk

1

Ответ:

20

Пошаговое объяснение:

(2у - 3)² + (у - 3)(у + 3) + 12у =

(4у² - 12у + 9) + (у² + 3у - 3у - 9) + 12у =

(4у² - 12у + 9) + (у² - 9) + 12у =

4у² - 12у + 9 + у² - 9 + 12у = 5у²

у = -2

5у² = 5 * (-2)² = 5 * 4 = 20

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