Question

Решение и ответ,срочно прошу плиз с 197 по 212

Answer 1

$\sqrt{a {}^{2} + b {}^{2} } = \sqrt{( - 9) {}^{2} + 40 {}^{2} } = \sqrt{81 + 1600} = \sqrt{1681} = \sqrt{41 {}^{2} } = 41$

$\sqrt{a {}^{2} + b {}^{2} } = \sqrt{28 {}^{2} + ( - 96) {}^{2} } = \sqrt{784 + 9216} = \sqrt{10000} = \sqrt{100 {}^{2} } = 100$

$\sqrt{a {}^{2} + b {}^{2} } = \sqrt{ {( - 96)}^{2} + {( - 72)}^{2} } = \sqrt{9216 + 5184} = \sqrt{14400 } = \sqrt{120 {}^{2} } = 120$

$\sqrt{ - 2x + {y}^{2} } = \sqrt{ - 2 \times ( - 154) + ( - 4) {}^{2} } = \sqrt{308 + 16} = \sqrt{324} = \sqrt{ {18}^{2} } = 18$

$\sqrt{ - 8x + {y}^{2} } = \sqrt{ - 8 \times 40 + 24 {}^{2} } = \sqrt{ - 320 + 576} = \sqrt{256} = \sqrt{ {16}^{2} } = 16$

$\sqrt{6x + {y}^{2} } = \sqrt{6 \times 32 + ( - 13) {}^{2} } = \sqrt{192 + 169} = \sqrt{361} = \sqrt{19 {}^{2} } = 19$

$\sqrt{3x + {y}^{2} } = \sqrt{3 \times ( - 195) + 29 {}^{2} } = \sqrt{ - 585 + 841} = \sqrt{256} = \sqrt{16 {}^{2} } = 16$

$\frac{ \sqrt{a} }{ \sqrt{c} - 3} = \frac{ \sqrt{361} }{ \sqrt{16} - 3 } = \frac{ \sqrt{ {19}^{2} } }{ \sqrt{ {4}^{2} } - 3 } = \frac{19}{4 - 3} = 19$

$\frac{ \sqrt{a} }{ \sqrt{c} - 4} = \frac{ \sqrt{196} }{ \sqrt{81} - 4} = \frac{ \sqrt{ {14}^{2} } }{ \sqrt{9 {}^{2} } - 4 } = \frac{14}{9 - 4} = \frac{14}{5} = 2.8$

$\frac{ \sqrt{a} }{ \sqrt{c} - 4} = \frac{ \sqrt{9} }{ \sqrt{361} - 4} = \frac{ \sqrt{ {3}^{2} } }{ \sqrt{ {19}^{2} } - 4 } = \frac{3}{19 - 4} = \frac{3}{15} = \frac{1}{5} = 0.2$

$\frac{ \sqrt{a} }{ \sqrt{c} + 1 } = \frac{ \sqrt{400} }{ \sqrt{1} + 1} = \frac{ \sqrt{20 {}^{2} } }{1 + 1} = \frac{20}{2} = 10$

$\frac{ \sqrt{a} }{ \sqrt{c} - 2 } = \frac{ \sqrt{0.81} }{ \sqrt{2.89} - 2} = \frac{ \sqrt{0.9 {}^{2} } }{ \sqrt{ {1.7}^{2} } - 2 } = \frac{0.9}{1.7 - 2} = - \frac{0.9}{0.3} = - 3$

$\frac{ \sqrt{a} }{ \sqrt{c} + 6 } = \frac{ \sqrt{0.36} }{ \sqrt{2.25} + 6 } = \frac{ \sqrt{0.6 {}^{2} } }{ \sqrt{ {1.5}^{2} } + 6 } = \frac{0.6}{1.5 + 6} = \frac{0.6}{7.5} = \frac{6}{75} = \frac{2}{25} = 0.08$

$\frac{ \sqrt{a} }{ \sqrt{c} - 2} = \frac{ \sqrt{2.25} }{ \sqrt{3.61} - 2 } = \frac{ \sqrt{ {1.5}^{2} } }{ \sqrt{ {1.9}^{2} } - 2 } = \frac{1.5}{1.9 - 2} = - \frac{1.5}{0.1} = - 15$

$\frac{1}{ \sqrt{a} } - \sqrt{b} = \frac{1}{ \sqrt{4} } - \sqrt{64} = \frac{1}{ \sqrt{ {2}^{2} } } - \sqrt{ {8}^{2} } = \frac{1}{2} - 8 = 0.5 - 8 = - 7.5$

$\frac{1}{ \sqrt{a} } - \sqrt{b} = \frac{1}{ \sqrt{100} } - \sqrt{324} = \frac{1}{ \sqrt{ {10}^{2} } } - \sqrt{ {18}^{2} } = \frac{1}{10} - 18 = 0.1 - 18 = - 17.9$