Question

х-6/2-3=х/3

|3(x-5)+1|=2

Answer 1

х-6/2-3=х/3

x-3-3=x/3

x-6=x/3

3x-18=x

3x-x=18

2x=18

x=9

|3(x-5)+1|=2

|3x-15+1|=2

|3x-14|=2

3x-14=±2

$x_{1}$ = 16/3

$x_{2}$ = 4

Answer 2

$\displaystyle\bf\\1)\\\\\frac{x-6}{2} -3=\frac{x}{3}\\\\\\\frac{x-6}{2}\cdot 6-3\cdot 6=\frac{x}{3}\cdot 6\\\\\\(x-6)\cdot 3-18=2x\\\\3x-18-18=2x\\\\3x-2x=36\\\\x=36\\\\\\2)\\\\\Big|3(x-5)+1\Big|=2\\\\\\\left[\begin{array}{ccc}3(x-5)+1=-2\\3(x-5)+1=2\end{array}\right\\\\\\\left[\begin{array}{ccc}3x-15+1=-2\\3x-15+1=2\end{array}\right\\\\\\\left[\begin{array}{ccc}3x=12\\3x=16\end{array}\right\\\\\\\left[\begin{array}{ccc}x=4\\x=5\dfrac{1}{3} \end{array}\right$