Question

(х+3)²-(х-2)(х+2)=0
решите уравнение
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Answer 1

Ответ:

$-\frac{13}{6}$

Объяснение:

$(x+3)^{2} -(x-2)(x+2)=0\\(x+3)(x+3)-(x-2)(x+2)=0\\x^{2} +3x+3x+9-(x-2)(x+2)=0\\x^{2} +6x+9-(x-2)(x+2)=0\\x^{2} +6x+9-(x^{2} +2x-2x-4)=0\\x^{2} +6x+9-(x^{2}-4)=0\\x^{2} +6x+9-x^{2}+4=0\\6x+13=0\\6x=-13\\x=-\frac{13}{6}$