Question

Реши систему уравнений: 2x +10y = 27 4x-5y=8​

Answer 1

Ответ:

$2x + 10y = 27 \\ 4x - 5y = 8 \\ \\ 2x = 27 - 10y \\ 2(27 - 10y) - 5y = 8 \\ \\ 2x = 27 - 10y \\ 54 - 20y - 5y = 8 \\ \\ 2x = 27 - 10y \\ 46 = 25y \\ \\ 2x = 27 - 10y\\ y = \frac{46}{25} \\ \\ 2x = 27 - 10y \\ y = 1 \frac{21}{25} \\ \\ 2x = 27 - 10 \times 1.84\\ y = 1.84 \\ \\ 2x = 27 - 18.4 \\ y = 1.84 \\ \\ 2x = 8.6 \\ y = 1.84 \\ \\ x = 4.3 \\ y = 1.84$