Question

Найди координаты вершины параболы y=5x^2+5x+11​

Answer 1

$y = 5 {x}^{2} + 5x + 11 \\ a = 5\\ b = 5 \\ c = 11 \\ x_{o} = - \frac{b}{2a} = - \frac{5}{2 \times 5} = - \frac{1}{2} = - 0.5 \\ y_{o} = - \frac{ {b}^{2} - 4ac }{4a} = - \frac{ {5}^{2} - 4 \times 5 \times 11 }{4 \times 5} = \\ = - \frac{25 - 220}{20} = - \frac{ - 195}{20} = \frac{39}{4} = 9.75$