Предмет: Химия, автор: xoxixixoxox

Виведіть формулу вуглеводню, масова частка Карбону в якому складає 83,333%, a густина за киснем 2,25. Визначте молекулярну формулу вуглеводню, назвіть його.

Ответы

Автор ответа: Abduuz

Ответ:

Углеводород = углерод + водород

Найдём молярную массу углеводорода:

D(O2) = 2,25

M = 2,25 × 32 = 72 г/моль

Найдём массу углерода:

72 × 0,8333 = 60 гр углерода ---> 60/12 = 5 моль углерода

72 - 60 = 12 гр водорода -----> 12/12 = 12 моль водорода

C:H = 5 : 12 = C5H12 это пентан

Ответ: C5H12 (пентан)

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SIGHT INTO HISTORY
It’s high time to confess honestly hardly anybody knows the real history of Khrystynopil. However, it is a sacred duty to know the main points of our history. How was our town founded? How far does its roots go back into history? Who settled here?
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