Предмет: Алгебра, автор: viktoriaberulina75

Упростите выражение:
(Cos^2a-ctg^2a)sin^2a

Ответы

Автор ответа: natalyabryukhova
0

Ответ:

\displaystyle \bf    ( cos^2\alpha -ctg^2\alpha )\cdot sin^2\alpha=-cos^4\alpha

Объяснение:

Упростить выражение:

\displaystyle \bf    ( cos^2\alpha -ctg^2\alpha )\cdot sin^2\alpha

Надо знать:

\boxed {\displaystyle \bf     ctg\;\alpha =\frac{cos\;\alpha }{sin\;\alpha } }\;\;\;\;\;\boxed {\displaystyle \bf     sin^2\alpha +cos^2\alpha =1 }

\displaystyle     ( cos^2\alpha -ctg^2\alpha )\cdot sin^2\alpha=\left(cos^2\alpha -\frac{cos^2\alpha }{sin^2\alpha } \right)\cdot sin^2\alpha =\\\\=cos^2\alpha \cdot sin^2\alpha -\frac{cos^2\alpha }{sin^2\alpha } \cdot sin^2\alpha =\\\\=cos^2\alpha \;sin^2\alpha -cos^2\alpha =cos^2\alpha (sin^2\alpha -1)=\\\\=-cos^2\alpha (1-sin^2\alpha )=-cos^2\alpha \cdot cos^2\alpha =-cos^4\alpha

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