Question

Решите уровнение 16x^3-8x^2+x=0

Answer 1

Объяснение:

$16 {x}^{3} - 8 {x}^{2} + x = 0 \\ x( 16{x}^{2} - 8x + 1) = 0 \\ 1)x = 0 \\ 2)16{x}^{2} - 8x + 1= 0 \\ (a = 16 \: b = - 8 \: c = 1) \\ d = {b}^{2} - 4ac = 64 - 64 = 0 = 0 \\ x = - \frac{b}{2a} = \frac{8}{32} = 0.25 \\ (0 \: \: 0.25)$