Question

{x²-64/y+3=0 9-y²/x-8=0

Answer 1

$\displaystyle\bf\\\left \{ {{\dfrac{x^{2}-64 }{y+3} =0} \atop {\dfrac{9-y^{2} }{x-8} =0}} \right.\\\\\\\left \{ {{x^{2} -64=0 \ \ ; \ \ y+3\neq 0} \atop {9-y^{2} =0 \ \ ; \ \ x-8\neq 0}} \right. \\\\\\\left \{ {{x^{2} =64 \ \ ; \ \ y\neq -3} \atop {y^{2} =9 \ \ ; \ \ x\neq 8}} \right. \\\\\\\left \{ {{x_{1} =-8 \ \ ; \ \ x_{2} =8-neyd \ \ ; \ \ y\neq -3} \atop {y_{1}=3 \ \ ; \ \ y_{2} =-3-neyd \ \ ; \ \ x\neq 8}} \right. \\\\\\Otvet \ : \ (-8 \ ; \ 3)$