Предмет: Физика, автор: baha87056002008

В воду погружено тело из алюминия объемом 0,2 дм3. (4) ρ_алю= 2700^ кг/м^3 ρ_вода= 10^3 кг/м^3, g = 9,8 H/ кг Определить следующие количества, используя данные значения​

Ответы

Автор ответа: NikitaYakushev21
1

Ответ:

Объяснение:

Масса алюминиевого тела:

m = V * ρ_алю = 0.2 дм^3 * 2700 кг/м^3 = 540 г

Плавучесть алюминиевого тела:

F_плав = m * g = 540 г * 9.8 H/кг = 5292 H

Выталкивающая сила Архимеда, действующая на тело в воде:

F_Арх = V * ρ_вода * g = 0.2 дм^3 * 10^3 кг/м^3 * 9.8 H/кг = 196 H

Так как F_плав > F_Арх, то тело будет плавать на поверхности воды.

Автор ответа: bakesovanurdana52
0

0,2дм:/-3(4)=2700кг/м

2700кг/м -10,3кг/м

2700>10,3>9,8/3, g

Объяснение:

ЭТО ПРАВИЛЬНО ЭТО ПРАВДА

ЭСЛИ ЧТО У МЕНЯ ЕСТЬ ПРУФ

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