Question

Решить уравнение через дискриминант
$8 - 2t + t^{2} = -2 - 5t + 2t^{2}$

Answer 1

$\displaystyle\bf\\8-2t+t^{2} =-2-5t+2t^{2} \\\\-2-5t+2t^{2}-8+2t-t^{2} =0\\\\t^{2} -3t-10=0\\\\D=(-3)^{2} -4\cdot(-10)=9+40=49=7^{2} \\\\\\t_{1} =\frac{3-7}{2} =\frac{-4}{2} =-2\\\\\\t_{2} =\frac{3+7}{2} =\frac{10}{2} =5\\\\\\Otvet \ : \ -2 \ ; \ 5$