Question

решите систему 
2y-x=7
x^2-xy-y^2=29

Answer 1

x=(2y-7) (2y-7)²-y(2y-7)-y²-29=0 4y²-28y+49-2y²+7y-y²-29=0 y²-21y+20=0 D=(-21)²-4*1*20=441-80=361=√361=19 y1=(-(-21)+19)/2*1=40/2 y1=20 y2=(-(-21)-19)/2=2/2 y2=1 x1=(2y1-7)=(2*20-7)=(40-7) x1=33 x2=(2y2-7)=(2*1-7)=(2-7) x2=-5