Question

помогите немогу решить​

Answer 1

Ответ:

$1)4-x=2\frac{1}{7} \\\\\\4-x=\frac{15}{7} \\\\-x=\frac{15}{7} -4\\\\-x=-\frac{13}{7} \\\\x=\frac{13}{7} \\\\x=1\frac{6}{7}$

$2)x-2\frac{7}{13} =10\frac{6}{13} \\\\x-\frac{33}{13} =\frac{136}{13} \\\\x=\frac{136}{13} +\frac{33}{13} \\\\x=13$

$3)x+4\frac{8}{11} =11\\\\x+\frac{52}{11} =11\\\\x=11-\frac{52}{11} \\\\x=\frac{69}{11} \\\\x=6\frac{3}{11}$

наче так