Предмет: Физика, автор: zetpisbajdias446

При стрельбе вверх стрела массой 50 г в момент начала движения имела полную механическую энергию 30 Дж. Какой высоты достигнет стрела?

Ответы

Автор ответа: maestro6835

1

В момент начала движения потенциальная энергия стрелы Ek равна нулю, поэтому полная энергия в начальный момент совпадает с кинетической энергией стрелы:
E0=Ek+Ep=Ek=30 Дж
В момент достижения стрелой максимальной высоты кинетическая энергия обращается в нуль, а потенциальная энергия достигает максимального значения. И так как,
Ek=Ep,
то
mgh=Ek
h=Ek/mg=30/0.05*10=60 м

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