Question

решите систему
x^2+y^2=9,y-3=x

Answer 1

Ответ:

$\left \{ {{x^2+y^2=9} \atop {y-3=x}} \right. \\\\y = x + 3\\\\x^2 + (x + 3)^2 = 9\\\\x^2 + x^2 + 6x + 9 = 9\\2x^2 + 6x = 0\\2x(x + 3) = 0\\x1 = 0; x2 = -3\\y1 = 0 + 3 = 3, y2 = -3 + 3 = 0$