Question

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Answer 1

$\displaystyle\bf\\1)\\\\x^{3} -x=0\\\\x\cdot(x^{2} -1)=0\\\\x\cdot(x-1)\cdot(x+1)=0\\\\\\\left[\begin{array}{ccc}x=0\\x-1=0\\x+1=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =0\\x_{2}=1 \\x_{3}=-1 \end{array}\right\\\\\\Otvet \ : \ 0 \ , \ 1 \ ; \ -1\\\\\\2)5x^{3} -125x=0\\\\5x\cdot(x^{2} -25)=0\\\\5x\cdot(x-5)\cdot(x+5)=0\\\\\\\left[\begin{array}{ccc}x=0\\x-5=0\\x+5=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =0\\x_{2} =5\\x_{3} =-5\end{array}\right$

$\displaystyle\bf\\Otvet \ : \ 0 \ , \ 5 \ , \ -5$