Question

ПОМОГИТЕ ДАЮ 50 БАЛЛОВ​

Answer 1

у = х² - 4х + 3

$a) \: x \: \epsilon \: ( - \infty ; \: + \infty ) \\ b) \: {x}^{2} - 4x + 3 = 0 \\ po \: \: \: teoreme \: \: \: vieta \\ {x}^{2} + bx + c = 0\\ x_{1} + x_{2} = - b\\ x_{1} x_{2} = c \\ x_{1}  +  x_{2} = 4 \\ x_{1} x_{2} =3  \\ x_{1} = 1 \\ x_{2} = 3 \\ c) \: y' =2 {x}^{2 - 1} - 4x {}^{1 - 1} = 2x - 4 \\ 2x - 4 = 0 \\ 2x = 4 \\ x = 4 \div 2 \\ x = 2 \\ - - - - - [2] + + + + + \\ x_{min} = 2 \\ y_{min} = {2}^{2} - 4 \times 2 + 3 = 4 - 8 + 3 =7 - 8 = - 1$