Question

(3Х+у)2кв
(а-2в)2кв
(3а-4)3куб
(Х+6)3куб

Answer 1

$9x {}^{2} + 6xy + y { \\ }^{2}$

$a {}^{2} - 2ab + 4b {}^{2}$

$27a {}^{3} - 108a {}^{2} + 144a - 64$

$x ^{3} - 18x {}^{2} + 108x - 216$