Question

log по основанию 2/7 (7-2х)/(3х+5)=0

Answer 1

log по основанию 2/7 (7-2х)/(3х+5)=0
одз 
=============-5/3========7/2======
--------------------     +++++++++  -----------
x=(-5/3 7/2)
(7-2x)/(3x+5)=1
7-2x=3x+5
5x=2
x=2/5