Question

допоможіть будь ласка
90 Баллов ​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{AB}{SinC} =\frac{\sqrt{2} }{Sin45^\circ} =\frac{\sqrt{2} }{\frac{1}{\sqrt{2} } } =\sqrt{2} \cdot \sqrt{2} =2$

2) По теореме синусов :

$\displaystyle\bf\\\frac{BC}{SinA} =\frac{AB}{SinC} \\\\\\\frac{BC}{Sin30^\circ } =2\\\\\\BC=2\cdot Sin30^\circ=2\cdot\frac{1}{2} =1\\\\\\3)\\\\\frac{AB}{SinC} =2R\\\\\\2=2R\\\\\\R=1$