Предмет: Химия, автор: MRFNAFSY

3) смешали 2 раствора-450 г 20% р-на сли и 130 г 30% раствора соли. Нужно вычислить массовую долю соли в полученном растворе
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Автор ответа: dyexfnf
0

Ответ:

Объяснение:

Дано:                                                            

m₁ = 450 г

ω₁ = 20 %, или 0,2

m₂ = 130 г

ω₂ = 30 %, или 0,3

Найти: ω₃ - ?

Найдем массу соли в первом и втором растворах:

m₁(соли) = m₁ * ω₁ = 450 * 0,2 = 90 г

m₂(соли) = m₂ * ω₂ = 130 * 0,3 = 39 г

Общее количество соли в новом растворе:

m(соли) = m₁(соли) + m₂(соли) = 90+ 39 = 129 г

Масса нового раствора:

m(н.р.) =  m₁ + m₂ = 450 + 130 =580 г

Вычислим массовую долю соли в полученном растворе:

ω₃ = m(соли)/m(н.р.) * 100% = 129/580 * 100% = 22,24%

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