Question

(Х2у2-1)(х2у2+1) (х4у4+1) х=2, у= -0,5

Answer 1

(х^2у^2-1)(х^2у^2+1) (х^4у^4+1) = (х^4у^4-1)(х^4у^4+1) = (х^4у^4-1)(x^4y^4+1) = (x^4y^4-1)(x^4y^4+1)

Значение выражения при x=2 и y=-0.5:

(2^4 * (-0.5)^4 -1) * (2^4 * (-0.5)^4 +1) = (0.0625 - 1) * (0.0625 + 1) = -0.9375 * 1.0625 = -1