Question

Решить систему уравнений:
у= х+2
4у+х в квадрате =8

Answer 1

$left { {{y=x+2} atop {4y+ x^{2} =8}} right. left { {{y=x+2} atop {4x+8+ x^{2} =8}} right. left { {{y=x+2} atop { x^{2} +4x=0}} right. left { {{y=x+2} atop {x(x+4)=0}} right. left { {{x=0} atop {y=2}} right. left { {{x=-4} atop {y=-2}} right.$
Ответ: (0;2), (-4;-2)