Предмет: Алгебра, автор: shotnicheck37

f(x) = (x² - 1)x³
найти произведение функции в точке х0=-1

Ответы

Автор ответа: KRISTINAweb

1

Ответ:

0

Объяснение:

f(x) = (x² - 1)x³

f(x0) = f(-1) = ((-1)² - 1)*(-1)³= (1 - 1)*(-1)=0*(-1)=0

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